(2x^2+3x+9)/(2x+1)

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Solution for (2x^2+3x+9)/(2x+1) equation: 


D( x )

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

(2*x^2+3*x+9)/(2*x+1) = 0

2*x^2+3*x+9 = 0

2*x^2+3*x+9 = 0

DELTA = 3^2-(2*4*9)

DELTA = -63

DELTA < 0

1 = 0

1/(2*x+1) = 0

x belongs to the empty set

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